916 Checkerboard V1 Codehs Fixed __link__ File

# Function to print the board def print_board(board): for row in board: # Join elements with a space for proper formatting print(" ".join([str(x) for x in row])) # 1. Initialize an 8x8 board with all zeros board = [] for i in range(8): board.append([0] * 8) # 2. Use nested loops to assign 1s to specific indices # Row indices 0, 1, 2 are the top three rows # Row indices 5, 6, 7 are the bottom three rows for row in range(8): for col in range(8): # Check if the row should have pieces if row < 3 or row > 4: # Only set to 1 if (row + col) is even to create the pattern if (row + col) % 2 == 0: board[row][col] = 1 # 3. Display the final board print_board(board) Use code with caution. Copied to clipboard Key Logic & Fixes 💡

The 916 Checkerboard problem on CodeHS is a classic challenge that requires creating a checkerboard pattern using a loop. Here is a fixed and well-documented solution: 916 checkerboard v1 codehs fixed

if ((row + col) % 2 == 0) square.setColor(Color.red); else square.setColor(Color.black); # Function to print the board def print_board(board):

# Row Counter row_count = 8

import turtle

var SQUARE_SIZE = 50; for(var row = 0; row < 8; row++) for(var col = 0; col < 8; col++) var x = col * SQUARE_SIZE; var y = row * SQUARE_SIZE; var color = (row + col) % 2 === 0 ? "red" : "black"; var rect = new Rectangle(SQUARE_SIZE, SQUARE_SIZE); rect.setPosition(x, y); rect.setColor(color); add(rect); Display the final board print_board(board) Use code with